if x =root 2 then x²+10x-1
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Solution :-
Given ,
- x = √2
We need to find ,
- x² + 10x - 1
• Method of solving :
- By substituting tbe the value of ‘x’ in the given equation we have ,
⇒ x² + 10x - 1
⇒ ( √2 )² + 10 ( √2 ) - 1
⇒ 2 + 10√2 - 1
⇒ 2 - 1 + 10√2
⇒ x² + 10x - 1 = 1 + 10√2
Hence , x² + 10x - 1 = 1 + 10√2
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