If x=root 3+1/2 find value of 4x3+2x2-8x+7
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Answer:
10
Step-by-step explanation:
x= (√3+1)/2
=> x² = (√3+1)² /4 =( 3 + 1 + 2√3) / 4 = (2+√3)/2
x^3 = (2+√3)/2 * (√3+1)/2 = (2√3+3+2 + √3)/ 4 = (5+3√3)/4
So, 4x^3 + 2x² -8x +7
= 4* (5+3√3)/4 + 2*(2+√3)/2 - 8* (√3+1)/2 +7
= 5 + 3√3 + 2 + √3 - 4√3 - 4 +7
= 4√3- 4√3 +7 + 3
= 10
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