Question

If x=root 75+root 48,y=root 12-root 108,z=3/4×root 8×root 24,then x+y+z is

Answer 1

x=root75+root48
=root (5x 5 x 3) +root (2 x 2 x 2 x 2 x3)
=5root3 +4root3=9root3

y=root12-root108
=root (2 x 2 x 3) -root(2 x 2 x 3 x 3 x 3)
=2root3 -6root3 =-4root3

z=3/4 x root8 x root24
=3/4 x root (2 x 2 x 2) x root (2 x 2 x 2 x3)
=3/4 {2root2}{2root6}
=3root (2 x 6)
=6root3

now add x, y and z
x+y+z=9root3 -4root3 +6root3
=11root3