Question

If x=sin^3t/√cos2t, y=cos^3t+√cos2t
then find dy/dx
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Answer 1

Step-by-step explanation:

We have \( x=\frac{\sin ^{3} t}{\sqrt{\cos 2 t}} \) and \( y=\frac{\cos ^{3} t}{\sqrt{\cos 2 t}} \) \[ \ therefore \quad \frac{d x}{d t}=\frac{\sqrt{\cos 2 t } ...