if x sin cube theta + Y cos cube theta is sin theta cos theta and x sin theta is Y cos theta, prove that X square + Y square is 1
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xsin³∅ + ycos³∅ = sin∅. cos∅
x.sin³∅ + cos²∅.(ycos∅) = sin∅.cos∅
use xsin∅= ycos∅ in above
xsin³∅ + cos²∅.xsin∅ = sin∅.cos∅
xsin∅( sin²∅ + cos²∅) = sin∅.cos∅
xsin∅ = sin∅.cos∅
x = cos∅
so, y = sin∅
now we know,
sin²∅ + cos²∅ = 1
put sin∅ = y
cos∅ = x
hence, x² + y² = 1
dailyhooper:
thanks.....appreciate it:)
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