Question

if x sinA = 5 and 7 cosecA = 6 SecA then find the valus of x​

Answer 1

Given:

$x$ $sin A = 5$

$7$ $cosecA = 6$ $Sec A$

To find:

The value of $x$

Step-by-step explanation:

$7$ $cosecA$ = $6 secA$

⇒ $\frac{7}{sinA}$ = $\frac{6}{cosA}$

⇒ $tanA$ = $\frac{7}{6}$

Let us calculate the value of $sinA$

$sinA$ = $\frac{7}{\sqrt{7^{2} +6^{2} } }$

$sinA =$ $\frac{7}{\sqrt{85} }$

Using this value in $x$ $sinA = 5$

⇒  $x$ × $\frac{7}{\sqrt{85} }$  = $5$

⇒  $x$ = $5$ × $\frac{\sqrt{85} }{7}$

Answer:

Therefore, the value of $x$ is $\frac{5\sqrt{85} }{7}$