if x square+ 1 upon x square =14 then the value of x+1 upon x
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• x² + (1/x²) = 14
Adding 2 on both sides -
• x² + (1/x²) + 2 = 14 + 2
We can write it as -
=> x² + (1/x²) + 2 × x × 1/x = 16
• Now using identity : a² + 2ab + b² = (a +b)²
=> [x + (1/x)]² = 16
=> x + (1/x) = √16
=> x + (1/x) = 4
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Thank you.. ;-)
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