Question

if X square + 1 upon x square is equal to 102 then find the value of x minus one upon x​

Answer 1

Answer:

Step-by-step explanation:

6

Answer 2

Answer:

$x-\frac{1}{x}=\pm 10$

Step-by-step explanation:

Given :$x^2+\frac{1}{x^2}=102$ ---A

To Find : $x-\frac{1}{x}$

Solution :

$x-\frac{1}{x}$

Squaring

$(x-\frac{1}{x})^2$

Identity : $(a-b)^2=a^2+b^2-2ab$

Using identity

$x^2+\frac{1}{x^2}-2$

Substitute the value from A

$102-2$

$100$

So, $(x-\frac{1}{x})^2=100$

$x-\frac{1}{x}=\pm 10$

Hence the value of $x-\frac{1}{x}=\pm 10$