Question

if X square + 1 upon x square is equals to 7 find 2 x square minus 2 upon 1 x square​

Answer 1

Answer:

${x}^{2} + \frac{1}{ {x}^{2} } = 7$

$2 {x}^{2} - \frac{2}{ {x}^{2} }$

${x}^{2} = 7 - \frac{1}{ {x}^{2} }$

${x}^{2} = \frac{7 {x - 1}^{2} }{ {x}^{2} }$

put in another eq

$2 \times \frac{7 {x }^{2} - 1 }{ {x}^{2} } - \frac{2 \times {x}^{2} }{7 {x }^{2} - 1}$

now solve it xd

you will get answer