If x square +1/x square=7 find 3x square-3/x square
Answers
Answer:
9√5
Step-by-step explanation:
Given-----> x² + 1 / x² = 7
To find ------> 3x² - 3 / x²
Solution-------> We know that,
1) ( a + b )² = a² + b² + 2ab
2) ( a - b )² = a² + b² - 2ab
3) ( a² - b² ) = ( a + b ) ( a - b )
ATQ, ( x² + 1 / x² ) = 7
Now, Applying first identity
( x + 1 / x )² = x² + 1 / x² + 2 ( x ) ( 1 / x )
= ( x² + 1 / x² ) + 2
= ( 7 ) + 2
= 9
=> ( x + 1 / x ) = 3
Now, applying second identity
( x - 1 / x )² = x² + 1 / x² - 2 ( x ) ( 1 / x )
= ( x² + 1 / x² ) - 2
= ( 7 ) - 2
=> ( x - 1 / x )² = 5
=> ( x - 1 / x ) = √5
Now,
3 x² - 3 / x² = 3 ( x² - 1 / x² )
= 3 { ( x )² - ( 1 / x )² }
Applying third identity , we get,
= 3 ( x + 1 / x ) ( x - 1 / x )
= 3 ( 3 ) ( √5 )
= 9 √5