Question

if X square + 10 X + Lambda is a perfect square then find the possible value of Lambda​

Answer 1

Step-by-step explanation:

I hope you would understand this afterwards please make it brainliest

Answer 2

You say that X² + 10X + L is a perfect square, then it should be in the form of a²+ b²+ 2ab,

Which is given to be X²+ 10X + L

= X² + 2(5)(X)+ L

In this expression, you can clearly see that the expression 2(5)(X) has 2 as the constant, X as the square root of the first term, and the last option here to put is 5, which should be the square root of the second term.

So, √lambada² = 5, then

Lambada = 5.

NOW, THAT'S THE CORRECT ANSWER.