if X square + bx + 188 is equal to zero has two distinct integer roots then how many values are possible for b
Attachments:
Answers
Answered by
2
2 distinct integer are possible for b
sanjai462:
don't see the question see the image
because it is a quadratic polinomial
there are 6 and 8 and 10 and 12
only these options were applicable
what is 6 8 10 and 12
are the options
in question it is 108 or 188
equation is x² + bx + 108=0
sorry for wrong question
now the equation is x²+bx+108=0
Similar questions