Question

Perimeter of a rectangle is 52 meters and area is 160 meter square what is its length

Answer 1

Let the length be 'a' cm and the breadth be 'b' cm.Then,                                          2(a+b)=52. (As it is the perimeter of the rectangle) _(i)                                          axb=160. (As it is the area)
    Substitute a=160/b in (i)
     b^2-26b+160=0.
    Thus,b=10 and a=16.(or vice versa).

Answer 2

Solution :-

As we know,

• Perimeter of Rectangle = 2 × (Length + Breadth)
• Area of Rectangle = Length × Breadth

First of all, we will find the length of the rectangle.

Let the length of the rectangle be x.

ATQ,

☛ 160m = x × 52m

☛ 160m ÷ 52m = x

☛ x = 3.07m

Hence, length of the Rectangle is 3.07m