if x square + kx -35=(x-5)(x+7)
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ĤĔŶ ÚŚĔŔ......
HERE IS UR ANSWER --
x^2 + kx - 35 = (x -5) ( x + 7)
Firstly solve the RHS...
(x-5) (x+7)
=x(x+7) -5(x+7)
=x^2 + 7x - 5x - 35
=x^2 + 2x - 35
NOW,,
=> x^2 + kx - 35 = x^2 + 2x - 35
So , we will replace k with 2 as per...
LHS = RHS
So, k = 2
HOPE IT HELPS U☺✌
HERE IS UR ANSWER --
x^2 + kx - 35 = (x -5) ( x + 7)
Firstly solve the RHS...
(x-5) (x+7)
=x(x+7) -5(x+7)
=x^2 + 7x - 5x - 35
=x^2 + 2x - 35
NOW,,
=> x^2 + kx - 35 = x^2 + 2x - 35
So , we will replace k with 2 as per...
LHS = RHS
So, k = 2
HOPE IT HELPS U☺✌
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