if x square minus x + 1 is equal to zero then find the value of x cube
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Step-by-step explanation:
x²-x+1=0
it is solved by qudratic formula
x=(-b+√b²-4ac)/2a
where a is coefficient of x²
b is coefficient of x and c is constant
so
a= 1 b=-1 c=1
x=(1+√1-4)/2
x=(1+√-3)/2
x=(1+i√3)/2 or (1-i√3)/2
now cube of x
(1+i√3)³/2³
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