If x square + y square = 80, find the value of ( x - y )square
vinayak1897:
What is the value of xy
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Answer:
X^2 + Y^2=80
(x+y)(x-y)=80
x-y=80/x+y
(x-y)^2= (80/x+y)^2
(x-y)^2= 6400/(x+y)^2
I think this cant be simplified further
Hopes this helps.
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