Question

if X square + Y square equal to 7 x y then prove that 2 log x + Y equal to log x + log Y + 2 log 3​

Answer 1

2log(x + y)  = logx + logy + 2Log3 if x² + y² = 7xy

Step-by-step explanation:

x² + y² = 7xy

adding 2xy both sides

=> x² + y² + 2xy = 7xy + 2xy

=> (x + y)² = 9xy

Taking log both sides

=> log (x + y)² = log (9xy)

=> 2log(x + y)  = log 9 + logx + logy

=> 2log(x + y)  = log 3² + logx + logy

=> 2log(x + y)  =2 log 3 + logx + logy

=>  2log(x + y)  = logx + logy + 2Log3

QED

Proved

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Answer 2

Answer:

2log(X+Y)

Step-by-step explanation:

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