if x=√t+1/√t,then dx/dt is equal to? Explain in steps?
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Hence the required answer is
(d) 1/(2√t ) - 1/( 2t√t )
Step-by-step explanation:
We will use the formula
d/dx ( x^m) = m x^( m - 1)
Now it is given that
x = √t + (1 /√t ) = t^(1/2) + t^(-1/2)
Now Differentiating both sides with respect to t we get
dx/dt
= d/dt [ t^(1/2) + t^(-1/2)]
= d/dt [ t^(1/2) ] + d/dt [ t^(-1/2)]
= (1/2) t^(1/2 - 1 ) - (1/2) t^(-1/2-1 ) ( using the formula)
= (1/2) t^( - 1/2 ) - (1/2) t^( - 3/2 )
= 1/(2√t ) - 1/( 2t√t )
Hence the required answer is (d) 1/(2√t ) - 1/( 2t√t )
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