If x = tan(e^-y) then show that day/dx = - (e^-y)/(1+x^2).
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x=tan(e^-y)
tan^(-1)x=e^-y
differen.
1/(1+x^2)=(-1)(e^-y) dy/dx
......ans
tan^(-1)x=e^-y
differen.
1/(1+x^2)=(-1)(e^-y) dy/dx
......ans
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