Question

if x tan square 60 plus 3 sin square 60 minus 3 by 4 tan square 30 equal to 6 then find x​

Answer 1

hope it helps you..........

and plz tell whether it is correct or not

Answer 2

The value of x is 4/3.

Step-by-step explanation:

Consider the given equation is

$x\tan^2(60)+3\sin^2(60)-\dfrac{3}{4}\tan^2 (30)=6$

We know that $\tan(60)=\sqrt{3},\sin (60)=\dfrac{\sqrt{3}}{2}, \tan(30)=\dfrac{1}{\sqrt{3}}$.

Substitute these values in given equation.

$x(\sqrt{3})^2+3(\dfrac{\sqrt{3}}{2})^2-\dfrac{3}{4}(\dfrac{1}{\sqrt{3}})^2=6$

$3x+3(\dfrac{3}{4})-\dfrac{3}{4}(\dfrac{1}{3})=6$

$3x+\dfrac{9}{4}-\dfrac{1}{4}=6$

$3x+2=6$

$3x=4$

$x=\dfrac{4}{3}$

Therefore, the value of x is 4/3.

#Learn more

Fin the value of 2tan30°/1+tan^2 30°.

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