If x= V2 is a solution of k x2 + root2x - 4 = 0 then find the value of k.
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Answer:
Step-by-step explanation:
short method:
Put value of x =√2 which is the solution/root of
kx^2 + (√2)x -4
-->k(√2)^2 + (√2)√2 -4 = 0
-->k(2) + 2 -4 =0
-->2k = 4-2
-->2k=2
-->k=1
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