If x varies inversaly as y and x =1/2 when y is 16.,find y when x=4
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xy=k=.5into16=8 i.e. 4y=8 y=2
Answered by
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x varies as 1/y
or x=k/y (k is proportionality constant)
Now x =1/2 and y=16
Therefore 1/2=k/16
or k =8
Again x=4
Therefore 4 =8/y
or y =2
or x=k/y (k is proportionality constant)
Now x =1/2 and y=16
Therefore 1/2=k/16
or k =8
Again x=4
Therefore 4 =8/y
or y =2
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