Question

plz answer urgently???????????????

Answer 1

heya it's Aastha.....

. [ ( x - a ) / ( x - b ) ] + [ ( x - b ) / ( x - a ) ] = ( a/b ) + ( b/a ), ... a ≠ b 

∴ { [ (x-a) / (x-b) ] - ( b/a ) } + { [ (x-b) / (x-a) ] - ( a/b ) } = 0 

∴ { [ a(x-a) - b(x-b) ] / [ a(x-b) ] } + { [ b(x-b) - a(x-a) ] / [ b(x-a) ] } = 0 

∴ [ a(x-a) - b(x-b) ] { [ 1 / [ a(x-b) ] - [ 1 / [ b(x-a) ] } = 0 

∴ a(x-a) = b(x-b) 

∴ ax - a² = bx - b² 

∴ (a-b)x = a² - b² 

∴ (a-b)x = (a-b)(a+b) 

∴ x = a + b .....

I hope it help you