Math, asked by kumarrohit7142, 1 year ago

If x varies inversely as (y2 - 1) and x is equal to 24 when y = 10, then the value of x when y = 5 is

Answers

Answered by Lohithachowdhary
19
look at the picture. You will get the answer
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Answered by Sahith423
22

Answer: 99

Step-by-step explanation:

Given x varies inversely as (y^2 - 1)

x = k * ( 1 / (y^2 - 1))

x = k ÷ (y^2 - 1)

Given x = 24 for y = 10

24 = k ÷ ( 10^2 - 1)

24 = k ÷ (100-1)

k = 24 * 99

For y= 5 x= ?

x = k ÷ ( y ^ 2 - 1)

x = 24 * 99 ÷ ( 5 ^2 - 1)

x = 24 * 99 ÷ 24

x= 99

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