If(x) = x²-1, then value of P(1) *P(-1) is?
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Answer:
Given p(x) = x³-x²+x+1
so, p(1) = (1)³-(1)²+1+1 = 2.
and p(-1) = -1-1+1+1 = 0
therefore , p(1)+p(-1) = 2+0 = 2. and
{p(1)+p(-1)}/2 = 2/2 = 1.
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