Question

If (x)=x2-5x-6find the values p(1),p(2),p(3),p(0),p(-1),p (-2), p(-3)

Answer 1

Step-by-step explanation:

P(x) = x^2 - 5x - 6

P(1)

$= {1}^{2} - 5(1) - 6 \\ = 1 - 5 - 6 \\ = 1 - 11 \\ = - 10$

P(2)

$= {2}^{2} - 5(2) - 6 \\ = 4 - 10 - 6 \\ = 4 - 16 \\ = - 12$

P(3)

$= {3}^{2} - 5(3) - 6 \\ = 9 - 15 - 6 \\ = 9 - 21 \\ = - 12$

P(0)

$= {0}^{2} - 5(0) - 6 \\ = 0 - 0 - 6 \\ = - 6$

P(-1)

$= { - 1}^{2} - 5( - 1) - 6 \\ = 1 + 5 - 6 \\ = 6 - 6 \\ = 0$

P(-2)

$= { - 2}^{2} - 5( - 2) - 6 \\ = 4 + 10 - 6 \\ = 14 - 6 \\ = 8$

P(-3)

$= { - 3}^{2} - 5( - 3) - 6 \\ = 9 + 15 - 6 \\ = 21 - 6 \\ = 15$

hope you get your answer