if x+y+1=0 prove that x²+y²+1=3xy
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if x+y+1=0 prove that x²+y²+1=3xy
SOLUTION : -
→ here, we have x + y + 1 = 0
then, x + y = -1............( Equ 1 )
By Taking cube on both the sides, we get
( x + y ) ³ = ( -1 )³
→ x ³ + y ³ + 3x² y + 3xy² = -1
→ x ³ + y ³ + 3xy ( x+ y ) = -1
→ x³ + y ³ + 3xy(-1) = -1
Therefore, by using ( Equ 1 ) ,we get ;
→ x³ + y ³ + 1 = 3xy
hence , proved
SOLUTION : -
→ here, we have x + y + 1 = 0
then, x + y = -1............( Equ 1 )
By Taking cube on both the sides, we get
( x + y ) ³ = ( -1 )³
→ x ³ + y ³ + 3x² y + 3xy² = -1
→ x ³ + y ³ + 3xy ( x+ y ) = -1
→ x³ + y ³ + 3xy(-1) = -1
Therefore, by using ( Equ 1 ) ,we get ;
→ x³ + y ³ + 1 = 3xy
hence , proved
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