if x:y= 1:3,
then find the density of objects.
brain list question.
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I have done this for the same system in air . hope someone else will do the above
Here moment of force on S1 = M1gX = volume x density(p1)g x X
= (4/3)π(2r)³ p1 X = 8 x (4/3)πr³p1X .............eq1
now for S2 = M2gY = (4/3)πr³p2gY ....................eq2
now according to principle of moments and from eq 1 and 2
8 x (4/3)πr³p1gX = (4/3)πr³p2gY
⇒ 8 x p1X = p2Y
⇒X/Y = (p2/p1)x 1/8
⇒1/3 = (p2/p1)x 1/8
⇒p2/p1 = 8/3
HENCE , WE CAN FIND THE RATIO OF THEIR DENSITIES WHICH IS
DENSITY OF S2 : DENSITY OF S1 = 8 : 3
Here moment of force on S1 = M1gX = volume x density(p1)g x X
= (4/3)π(2r)³ p1 X = 8 x (4/3)πr³p1X .............eq1
now for S2 = M2gY = (4/3)πr³p2gY ....................eq2
now according to principle of moments and from eq 1 and 2
8 x (4/3)πr³p1gX = (4/3)πr³p2gY
⇒ 8 x p1X = p2Y
⇒X/Y = (p2/p1)x 1/8
⇒1/3 = (p2/p1)x 1/8
⇒p2/p1 = 8/3
HENCE , WE CAN FIND THE RATIO OF THEIR DENSITIES WHICH IS
DENSITY OF S2 : DENSITY OF S1 = 8 : 3
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