Question

If (x+y,1)=(3,x−y) then (x,y) is​

Answer 1

Answer:

Add two equations

(x+y)+(x-y)=3+1

x+x+y-y=4

2x+0=4

2x=4

x=4/2

x=2

Replace x with 2 on any of two equations

2+y=3

y=3–2

y=1

Or

2-y=1

-y=1–2

-1y=-1

y=-1/-1

y=1

Finally substitute value of x and y in the required

x/y=2/1=2

simple :)

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#loki

Answer 2

$\color{red}\huge{\underline{\underline{\bf GIVEN\dag}}}$

• $(x + y,1) = (3,x - y)$

$\color{red}\huge{\underline{\underline{\bf SOLUTION\dag}}}$

$\tt equating \: coordinates :$

$x + y = 3...(1)$

$x - y = 1...(2)$

$\tt adding \: (1) \: and \: (2)$

$(x + y) + (x - y) = 3 + 1$

$\implies 2x = 4$

$\therefore x = 2$

$\tt substituting \:(x = 2) \: in \: (1) :$

$\implies 2 + y = 3$

$\therefore y = 1$

$\orange{ \boxed{\therefore (x,y) = (2,1)}}$

HOPE THIS HELPS!!