if x+y=1 and xy=12 find :- i)x-y and x^2 - y^2
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Answer:
Step-by-step explanation:
given,
x+y = 1 and xy = 12
take (x+y) = 1
squaring on both sides,
(x+y)² = 1²
x²+y²+2(xy) = 1
=> x²+y²+2(12) = 1
=> x²+y² = 1-24
=> x²+y² = -23
consider, (x-y)²
= x²+y²-2(xy)
= -23 -2(12)
= -23 -24
= -47
=> x-y = √-47
so, x²-y² = (x+y)(x-y) = 1(√-47)
= √-47
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