Question

If √x+√y=√10.show that dy/dx+√y/x=0

Answer 1

Step-by-step explanation:

$\sqrt{x} + \sqrt{y} = \sqrt{10}$

$= > \frac{1}{2 \sqrt{x} } + \frac{1}{2 \sqrt{y} } \frac{dy}{dx} = 0$

$= > \frac{1}{2 \sqrt{y} } \frac{dy}{dx} = - \frac{1}{2 \sqrt{x} }$

$= > \frac{dy}{dx} = - \sqrt{ \frac{y}{x} }$

$= > \frac{dy}{dx} + \sqrt{ \frac{y}{x} } = 0$