Question

if x+y =12 and xy =14 find the value of x^2 +y^2​

Answer 1

Step-by-step explanation:

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Hint: We have been given the value of x + y and xy, so we can use the formula (x+y)2=x2+y2+2xy(x+y)2=x2+y2+2xy and then we will substitute the value of x + y and xy in the formula and then we will perform some algebraic operations to find the value of x2+y2x2+y2.

Complete step-by-step answer:

Let’s start our solution.

We know the value of x + y and xy, so the only formula that comes in our mind by seeing what is given and what we need find is (x+y)2=x2+y2+2xy(x+y)2=x2+y2+2xy

Now we have to substitute all the given values in the equation and then solve it,

So, substituting the value of x + y = 12 and xy = 14 in (x+y)2=x2+y2+2xy(x+y)2=x2+y2+2xy we get,

(12)2=x2+y2+2(14)(12)2=x2+y2+2(14)

Now taking all the constant to one side and the variable to other side we get,

x2+y2=144−28x2+y2=116x2+y2=144−28x2+y2=116

Hence, the value of x2+y2x2+y2 is 116.

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Answer 2

Answer:

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