if x+y=12 and xy=14, find the value of x square + y square
Answers
Answered by
5
your ans
given:-
x+y=12
xy=14
apply:- (x+y)2=x2+y2+2xy
(12)2=x2+y2+2×14
144-28=x2+y2
116=x2+y2
given:-
x+y=12
xy=14
apply:- (x+y)2=x2+y2+2xy
(12)2=x2+y2+2×14
144-28=x2+y2
116=x2+y2
anymouse:
hl9
Answered by
0
Equation 1: (x + y) = 12 ------- square both sides: (x + y)^2 = 12^2 ----> x^2 + 2(x)(y) + y^2 = 144
Equation 2: (x)(y) = 14
Take x(y) in equation 2 and substitute it as 14 into x(y) in equation 1:
x^2 + 2(14) + y^2 = 144
subtract 2(14) which is 28 to both sides of the equation:
x^2 + y^2 = 116
--------Hope it helps--------
Equation 2: (x)(y) = 14
Take x(y) in equation 2 and substitute it as 14 into x(y) in equation 1:
x^2 + 2(14) + y^2 = 144
subtract 2(14) which is 28 to both sides of the equation:
x^2 + y^2 = 116
--------Hope it helps--------
Similar questions