Question

If x+y=12 and xy=14, find the value of ( x²+y²)

Answer 1

Answer:

(x+y)² = x²+y²+2xy

=> (12)² = x²+y²+2× 14

=> 144 = x²+y² +28

=> 144-28 = x²+y²

=> 116 = x²+y²

Answer 2

Step-by-step explanation:

x+y=12

x²+y²+2xy=144

x²+y²+2×14=144

x²+y²+28=144

x²+y²=144-28

x²+y²=116