if x+y=12 and xy=14 find value of x
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Step-by-step explanation:
x + y =12... (1)
Multiplying throughout by xy, we get,
xy(x+y)=xy(12)
xy=14... (2)
Substituting (2) in (1),
14(x+y)=12(14)
14x +14y =168...(3)
Answered by
1
Answer:6+root22
6-root22
Step-by-step explanation:
(x+y) ^2=x^2+y^2+2xy
144=x^2+y^2+28
x^2+y^2=144-28
x^2+y^2=116
x^2+(12-x)^2=116
x^2+144+x^2-24x=116
2x^2-24x+28=0
x^2-12x+14=0
x=(12+root(144-56)) /2
x=(12+2root22)/2
x=6+root22
Or x=6-root22
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