Math, asked by kavitagulia430, 11 months ago

if x+y=12 and xy=14 find value of x​

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Answers

Answered by pingatsamarth2
0

Step-by-step explanation:

x + y =12... (1)

Multiplying throughout by xy, we get,

xy(x+y)=xy(12)

xy=14... (2)

Substituting (2) in (1),

14(x+y)=12(14)

14x +14y =168...(3)

Answered by Anonymous
1

Answer:6+root22

6-root22

Step-by-step explanation:

(x+y) ^2=x^2+y^2+2xy

144=x^2+y^2+28

x^2+y^2=144-28

x^2+y^2=116

x^2+(12-x)^2=116

x^2+144+x^2-24x=116

2x^2-24x+28=0

x^2-12x+14=0

x=(12+root(144-56)) /2

x=(12+2root22)/2

x=6+root22

Or x=6-root22

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