If x+y =12and xy=27 ,find the value of x^3+y^3
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Answered by
5
x^3+y^3=(x+y)^3-3xy(x+y)
= (12)^3-3×27(12)
= (1728)-272
= 756
= (12)^3-3×27(12)
= (1728)-272
= 756
swa101112:
sorry but this answer is not correct the right answer is 756
i have corrected it
Not correct!!!!!!
i have edited it
Answered by
5
(x+y)^3 = x^3+y^3+3xy(x+y)
(12)^3= x^3+y^3+(3×27×12)
1728=x^3+y^3 + 972
1728-972=x^3+y^3
756=x^3+y^3
(12)^3= x^3+y^3+(3×27×12)
1728=x^3+y^3 + 972
1728-972=x^3+y^3
756=x^3+y^3
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