Question

if x+y=12and xy=32 find the value of x²+y²​

Answer 1

Answer:

Step-by-step explanation:

Given that:  x+y=12 and xy = 32

Using the identity, (x+y)  

2

 = x  

2

+2xy+y  

2

 

⇒ (12)  

2

 =x  

2

+64+y  

2

 

⇒ 144 = x  

2

+y  

2

+64

⇒ 144−64 = x  

2

+y  

2

 

⇒ 80 = x  

2

+y  

2

 

The answer is x  

2

+y  

2

 = 80