Question

if x+y=12and xy=32 then find the value of x^2 +y^2​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Step-by-step explanation:

given =.x+y = 12

xy=32

find $x^{2}+y^{2}=?$

x+y = 12 (squaring on both side)

$x^{2}+y^{2}+ 2xy = 144 \\ x^{2}+y^{2}+2×32 = 144 \\ x^{2}+y^{2}=.144-2×32 \\ x^{2}+y^{2}=80$