Question

If (x - y) = 13 and xy = -5, then find the value of 1/3(x^2 + y^2)


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Answer 1

xy = -5

=> 2xy = -10 ...........................(i)

and

(x - y) = 13

=> (x-y)^2 = 169 ....................(ii)

Now,

(x-y)^2 = x^2 + y^2 + 2xy

=> x^2 + y^2 = (x-y)^2 + 2xy

=> x^2 + y^2 = 169 + (-10) ......(from i and ii)

=> x^2 + y^2 = 159

Thus,

1/3(x^2 + y^2) = 159/3 = 53

Answer 2

Answer:

Step-by-step explanation: