Question

if x+y=15 and x×y=44 then x²+y²={find it }​

Answer 1

Answer:

$15 < log_{ \binom{ \cot( \sec(?) ) }{?} }(?) \times \frac{?}{?}$

Answer 2

Answer:

137

(X+y)²=x²+y²+2xy

15²=x²+y²+2×44

225-88=x²+y²

137= x²+y²