Question

If x + y = 18, y + z = 24 and z + x = 22, then find the
value of (x² + y2 + 2 + 2xy + 2yz + 2zx)​

Answer 1

Answer:

x=8

Y=10

Z=14

64+100+2+160+280+224=830

Answer 2

Answer:

the ans is 750

Step-by-step explanation:

x + y = 18 ...... 1

y+ z = 24 .......2

z+x = 22 .......3

x = 18 -y .....4

z = 24 - y ..... 5

substitute 4 & 5 in 3

24 - y + 18 - y = 22

42 - 2y = 22

-2y = -20

y = 10

substitute y = 10 in 4 & 5

x = 8 & z = 14

substitute values of x , y & z in $(x^{2}  + 2y + 2 + 2xy +2yz +2zx)$

the value is 750 .