Question

if (x-y)² = 121xy , then 2log (x+y) =​

Answer 1

*Question:—

→ if (x-y)² = 121xy , then 2log (x+y) = ?

*Answer:—

From 1 :—

→ (x - y)² = 121xy

→ x² + y² - 2xy = 121xy

→ x² + y² + 2xy = 125xy

→ (x + y)² = 125xy

Applying log on both the sides :—

→ log(x + y)² = log(125xy)

→ 2log(x + y) = log125 + log(x) + log(y) ___(3)

From (2) and (3) :—

→ k = log25

Hope it helps you.

$@vikramjeeth$

Answer 2

Step-by-step explanation:

Given,

(x-y)² = 121xy

x²+y²-2xy = 121xy

x²+y² = 121xy + 2xy

x²+y² = 123xy

Also given,

2log (x+y)

W.K.T,

______________

m log a = log a^m

______________

=> log (x+y)²

=> log x²+y²+2xy

=> log 123xy + 2xy

=> log 125xy

W.K.T,

______________________

log abc = log a+log b+log c

______________________

=> log 125 + log x + log y

=> log 5³ + log x + log y

=> 3log5 + log x + log y.

I hope it helps you!!!