Math, asked by Farheen9176, 10 months ago

If x/y=(-2/3)3÷(3/5)-2 find the value of
(x/y) - 2
(x/y+ y/x) - 1​

Answers

Answered by adhyayan56
8

Step-by-step explanation:

value of (x/y)-2.

value of (x/y)=(-2/3)3÷(3/5)-2

(x/y)-2= (-2/3)×3÷(3/5)-2-2

=(-22/3)

value of (x/y+ y/x) - 1.

value of (x/y+ y/x) - 1.=

((-2/3)3÷(3/5)-2)+((-3/2)1/3÷(5/3)-2)-1

=(-16/3)+(-23/10)-1

=(-259/30)

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