Question

If (x+y)²=64 and (x-y)²=16, find the value of xy.

Plz Reply me fast

Answer 1

Hope this helps you ☺☺☺☺

Answer 2

$(x+y)^2 =64$

$x+y = \sqrt{64}$

x + y = 8   ----1equation
_________________

$(x-y)^2 = 16$

$x-y = \sqrt{16}$

x  -y =4      ----2equation 
__________________________

x + y =  8         -----1equation 

x - y = 4         -------2equation

Adding both equations,

x + y = 8 
x - y = 4

2x = 12 

$x = \frac{12}{2}$

x = 6 

Putting the value of x in 1equation.

x + y = 8 

6 +y =8 

y =8-6 

y = 2 

________________

x = 6 

y = 2

________________

x y = x × y 

x × y = 2 × 6 

xy = 12 

__________________



 i hope this will help you



-by ABHAY