Question

determine the integer whose product with (-1) is=(a) -22 (b) 37 (c) 0

Answer 1

Before getting into the answer, Remember these :

(1) Negative(-) times(x) Negative (-) = positive (+)
(2) Positive(+) times(x) Positive(+) = positive(+)
(3) Negative(-) times(x) Positive(+) = negative(-)

Now, The answer :

(a) The result should be -22,
We have -1,

To get negative from negative, We must multiply positive,

Now take out the signs, And think how much should be multiplied to 1, To get 22,

It's +22,

So the answer is +22,

(b) Result should be +37,
We have -1,

We need to get positive from negative, So we need to multiply negative,

=> Take out the signs and think how much should be multiplied to get 37 from 1,

It's 37,

So the answer is -37,

(c) ±0, Anything * 0 is 0, Except infinity,

=> -1 Should be Multiplied with 0, To get 0,

=> The answer is 0,

Therefore : The answers are :
(a) +22
(b) -37
(c) 0,

Hope you understand, Have a Great day :D,
Thanking you, Bunti 360 !.

Answer 2

Answer:

(a) 22 , (b) -37 and (c)0 are the required integers

Step-by-step explanation:

Explanation:

Integers - A number which is not a fraction but a whole number and it can be positive or negative.

Step 1:

(a) when we multiply 22 with -1 we get

-22 × -1 = 22     ( the product of two negative become positive )

(b) 37

When we multiply 37 with (-1) we get ,

37 × (-1) = -37  

(where product of positive and negative become negative )

Similarly , (c) 0

when we multiply 0 with (-1) we get

0 × (-1) = 0

Final answer:

Hence , 22 , -37 and 0 are the integers .

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