Question

if X + Y + 2 is equal to zero then the value of x cube + y cube + 8

Answer 1

$x + y + 2 = 0 \: \: then\\ = {x}^{3} + {y}^{3} + 8 \\ = ( x + y + 2)^{3} \\ = ( {0})^{3} \\ = 0$