if x - y =2, xy = 3, then find the value of xcube - ycube
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⭐⭐Hello friend...Ur answer is here⤵⤵
⚫ x-y=2 , xy=3
➡ (x-y)^2=x^2+y^2-2xy
➡ 2^2=x^2+y^2-2×3
➡ x^2+y^2=10
Now we find x^3-y^3
➡ x^3-y^3=(x-y)(x^2+y^2+xy)
➡ x^3-y^3=2×(10+3)
➡ x^3-y^3=26
I HOPE IT IS HELPFUL TO YOU
⚫ x-y=2 , xy=3
➡ (x-y)^2=x^2+y^2-2xy
➡ 2^2=x^2+y^2-2×3
➡ x^2+y^2=10
Now we find x^3-y^3
➡ x^3-y^3=(x-y)(x^2+y^2+xy)
➡ x^3-y^3=2×(10+3)
➡ x^3-y^3=26
I HOPE IT IS HELPFUL TO YOU
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