Question

if x+y=2z,then x/x-z+z/y-z=? options are 0,1,-1,2

Answer 1

Answer:

the answer should be:1 (one)

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Answer 2

given : $x+y = 2z$

To find : $\frac{x}{x-z}+\frac{z}{y-z}$

solution :

$\frac{x}{x-z}+\frac{z}{y-z}\\\\\text{taking LCM}\\\\\frac{xy-xz+zx-z^2}{(x-z)(y-z)}\\\\\frac{xy-z^2}{xy-xz-zy+z^2}\\\\\frac{xy-z^2}{xy-z(x+y)+z^2}$

given that x+y = 2z

thus ,

$\frac{xy-z^2}{xy-2z^2-z^2}\\\\\frac{xy-z^2}{xy-z^2}= 1$

hence , The value is 1

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