Question

if x:y = 3:1 then find value of (x3-y3) : (x3+y3)

Answer 1

Answer:

$\bf\,(x^3-y^3):(x^3+y^3)=13:14$

Step-by-step explanation:

$\textbf{Given:}$

$x:y=3:1$

$\text{Then,}$

$x=3k\;\;\&\;\;y=k$

$\text{Now}$

$\displaystyle\frac{x^3-y^3}{x^3+y^3}$

$=\displaystyle\frac{(3k)^3-k^3}{(3k)^3+k^3}$

$=\displaystyle\frac{27k^3-k^3}{27k^3+k^3}$

$=\displaystyle\frac{26k^3}{28k^3}$

$=\displaystyle\frac{13}{14}$

$\implies\boxed{\bf\,(x^3-y^3):(x^3+y^3)=13:14}$

Answer 2

Step-by-step explanation:

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