if x/y =(3/4)^-3÷(4/5)^0 find (x/y)^-2
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Given equations are xy+x+y=23
⇒x(y+1)=23−y
⇒x=y+123−y ........(i),
yz+y+z=27
⇒z(y+1)=27−z
⇒z=y+127−y ...........(ii)
and xz+x+z=41 .....(iii)
Substituting (i) and (ii), we get
(y+123−y)(y+127−y)+y+123−y+y+127−z=41⇒(y+1)2621+y2−50y+y+150−2y=41⇒(y+1)2621+y2−50y+(50−2y)(y+1)=41⇒621+
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